Order of Constructor Call with Inheritance in C++ | Order of Constructor Call with Inheritance in C++ In Hindi

Order of Constructor Call with Inheritance in C++ 

Base class constructors are always called in the derived class constructors. Whenever you create derived class object, first the base class default constructor is executed and then the derived class's constructor finishes execution.

Whether derived class's default constructor is called or parameterised is called, base class's default constructor is always called inside them.To call base class's parameterised constructor inside derived class's parameterised constructor, we must mention it explicitly while declaring derived class's parameterized constructor.

Fig: Order of Constructor Call with Inheritance in C++

Program:

#include<iostream.h>’

#include<conio.h>

class Base

{

int x;

public:

Base()

{

cout<<”base default constructor”;

} 

};

class Derived: public Base

{

int y;

public:

Derived()

{

cout<<”derived default constructor”;

}

Derived(int i)

{

cout<<”derived parameterized constructor”;

}

};

void main()

{

Base b;

  Derived d1;

Derived d2(10);

getch();

}

Output:

Base default constructor

Base default constructor

Derived default constructor

Base default constructor

Derived parameterized constructor