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Returning Reference In C++

The name of variable to reference return should done so if variable is reference type so function should be reference type which we needed.

If the reference variable is return type so function should returning reference we have a value which can replace form one place to another place so there  we have to use assignment operator.

Fig:Returning Reference In C++

Syntax:

returntype &functionname (&argument list)

{

function of body;

}

Program:

#include<iostream.h>

#include<conio.h>

char &replace(int a);

char name[30];

void main

{

cout<<”input string”;

cin>>name;

replace (5)=’c’;

cout<<name;

getch();

char &replace(int a)

{

return name[a];

}

Output:

Input value

Pramod

Pramcd